化简:(1)1-tanˆ2(x+y)/2tan(x+y) (2)sin4a/1+cos4a

问题描述:

化简:(1)1-tanˆ2(x+y)/2tan(x+y) (2)sin4a/1+cos4a

1)
=1/[2tan(x+y)/1-tan²(x+y)]
=1/[tan2(x+y)]
2)
=2sin2acos2a/(2cos²2a-1+1)
=sina2a/cos2a
=tan2a