因式分解 （a+b）²-1 -（x+2）²+16（x-1）² （3x+2y）²-（x-y）²
问题描述：
因式分解 （a+b）²-1 -（x+2）²+16（x-1）² （3x+2y）²-（x-y）²
答
（a+b）²-1
=(a+b+1)(a+b-1)
-（x+2）²+16（x-1）²
=(4(x-1))^2-(x+2)^2
=(4(x-1)-(x+2))(4(x-1)+(x+2)
=(4x-4-x-2)(4x-4+x+2)
=(3x-6)(5x-2)
=3(x-2)(5x-2)
（3x+2y）²-（x-y）²
=(3x+2y-(x-y))(3x+2y+(x-y))
=(3x+2y-x+y)(3x+2y+x-y)
=(2x+3y)(4x+y)
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谢谢
答
（a+b）²-1=（a+b+1)(a+b-1)-（x+2）²+16（x-1）²=[4(x-1)+(x+2)][4（x-1)-(x+2)]=(4x-4+x+2)(4x-4-x-2)=(5x-2)(3x-6)=3(x-2)(5x-2)（3x+2y）²-（x-y）²=[(3x+2y)+(x-y)][(3x+2y)-(x-y)]=(...