因式分解x^2-2x-4y^2+1

分类: 作业答案 • 2021-12-19 17:19:42

问题描述：

因式分解x^2-2x-4y^2+1

答

x^2-2x-4y^2+1
=x^2-2x+1-4y^2
=(x-1)^2-4y^2
=(x-1+2y)(x-1-2y)

答

x^2-2x-4y^2+1
=x^2-2x+1-4y^2
=(x-1)^2-4y^2(运用平方差公式,自己做吧)
=

答

x^2-2x-4y^2+1
=x^2-2x+1-4y^2按照x的降幂排列
=(x-1)^2-4y^2
=(x-1)^2-(2y)^2
=(x-1-2y)(x-1+2y) 逆用平方差公式进行因式分解

答

x^2-2x-4y^2+1
=x^2-2x+1-4y^2
=(x-1)^2-4y^2
=(x-1-2y)(x-1+2y)