已知8^m=12,4^n=6求2^6m-2n+1的值
问题描述：
已知8^m=12,4^n=6求2^6m-2n+1的值
答
2^6m-2n+1
=2^6m÷2^2n×2
=(2³)^2m÷(2²)^n×2
=(8^m)²÷4^n×2
=12²÷6×2
=48
答
答：
8^m=12：2^(3m)=12
4^n=6：2^(2n)=6
2^(6m-2n+1)
=2*[2^(3m)]^2/2^(2n)
=2*[(12)^2]/6
=144/3
=48
答
∵8^m=12
∴2^(3m)=12
∵4^n=6
∴2^(2n)=6
2^(6m-2n+1)
=[2^(6m)]÷[2^(2n)]×2
=[2^(3m)]²÷[2^(2n)]×2
=12²÷6×2
=144÷6×2
=24×2
=48