①(a-2b-c)(-a-2b-c) ②(m+2n-2)(m-2-2n)
问题描述:
①(a-2b-c)(-a-2b-c) ②(m+2n-2)(m-2-2n)
答
①(a-2b-c)(-a-2b-c)
=[(-2b-c)+a][(-2b-c)-a]
=(-2b-c)^2-a^2
=4b^2+c^2-4bc-a^2
②(m+2n-2)(m-2-2n)
=[m+(2n-2)][m-(2+2n)]
=m^2-(2n-2)^2
=m^2-4n^2+8n-4
答
①(a-2b-c)(-a-2b-c)
=-(a-2b-c)(a+2b+c)
=-[a²-(2b+c)²]
=-a²+4b²+4bc+c²
②(m+2n-2)(m-2-2n)
=(m-2+2n)(m-2-2n)
=(m-2)²-(2n)²
=m²-4m+4-4n²