(m-n/m^2-2mn+n^2-mn+n^2/m^2-n^2)*mn/n-1

分类: 作业答案 • 2021-12-19 16:58:31

问题描述：

答

原式=[(m-n)/(m-n)²-n(m-n)/(m+n)(m-n)]*mn/(n-1)
=[1/(m-n)-n/(m+n)]*mn/(n-1)
=[(m+n-mn+n²)/(m-n)(m+n)]*mn/(n-1)
=mn(m+n-mn+n²)/[(n-1)(m-n)(m+n)]