x/20=(x-32-32)/12

问题描述:

x/20=(x-32-32)/12

`12X=20(X-64)
12X=20X-1280
-8X=-1280
X=160

12X=20(X-64)
12X=20X-1280
8X=1280
X=160

12X=20(X-64)
12X=20X-20*64
12X=20X-1280
-8X=-1280
8X=1280
X=1280/8
X=160