[1-(0.2+1÷6)×(5/11)]÷0.75++怎么算?

问题描述:

[1-(0.2+1÷6)×(5/11)]÷0.75++怎么算?

[1-(0.2+1÷6)×(5/11)]÷0.75=(1-(1/5+1/6)*(5/11)/0.75=(1-(11/30)*(5/11)/0.75=(1-1/6)/(3/4)=(5/6)*(4/3)=10/9