解下列方程:(3x-2)^2=(x+4)^2

问题描述:

解下列方程:(3x-2)^2=(x+4)^2

(3x-2)^2=(x+4)^2
9x^2-12x+4=x^2+8x+16
8x^2-20X-12=0
2X^2-5X-3=0
(2X+1)(X-3)=0
X=-1/2或X=3

9x²-12x+4=x²+8x+16
8x²-20x-12=0
2x²-5x-3=0
(x-3)(2x+1)=0
x=-1/2或x=3

(3x-2)^2=(x+4)^2
(3x-2)^2-(x+4)^2=0
[(3x-2)+(x+4)][(3x-2)-(x+4)]=0
﹙4x+2)(2x-6)=0
4x+2=0,或2x-6=0
x=-½,或x=3