已知集合A={x丨log1/2(3-x)>-2}B={X丨5/x+2≥1}则A∩B
问题描述：
已知集合A={x丨log1/2(3-x)>-2}B={X丨5/x+2≥1}则A∩B
答
解log1/2(3-x)>-2=log1/2(1/2)^(-2)=log1/2(4)即log1/2(3-x)>log1/2(4)即0＜3-x＜4即-1＜x＜3A={x丨-1＜x＜3}5/x+2≥1即5/x+2-1≥0即5/x+2-（x+2）/(x+2）≥0即[5-（x+2）]/(x+2）≥0即（3-x）/(x+2）≥0即（x-3）/(...