用幂的性质运算:(根号3)×(3次根号9)÷(6次根号3)
问题描述:
用幂的性质运算:(根号3)×(3次根号9)÷(6次根号3)
答
根号3 × 3次根号9 ÷ 6次根号3
=3^(1/2)* 9^(1/3) ÷3^(1/6)
= 3^(1/2)* (3^2)^(1/3) * 3^(-1/6)
= 3^(1/2)* 3^(2/3) * 3^(-1/6)
=3^(1/2+2/3-1/6)
=3^1
=3