证明(sina+sinθ)*(sina-sinθ)=sin(a+θ)*sin(a-θ)

问题描述:

证明(sina+sinθ)*(sina-sinθ)=sin(a+θ)*sin(a-θ)

两边都打开,肯定能约掉

sin(a+θ)*sin(a-θ)=(sinacosθ+cosasinθ)*(sinacosθ-cosasinθ)=sin²acos²θ-cos²asin²θ=sin²a(1-sin²θ)-(1-sin²a)sin²θ=sin²a-sin²asin²θ-sin...