3(x^2-1)^2+18(1-x^2)+273(x²-1)²+18（1-x²）+27
问题描述：
3(x^2-1)^2+18(1-x^2)+27
3(x²-1)²+18（1-x²）+27
答
=3【(x²-1)²-6(x²-1)+9】
=3(x²-1-3)²
=3（x²-4）²
= 3（x-2）²（x+2）²
答
1)3(x²-1)²+18（1-x²）+27=0
2)(1-x²)²+6（1-x²）+9=0
3) (1-x² + 3)² = 0
4) 1-x² + 3 = 0
5) x² = 4
6) x = 2, x = -2
答
原式=3(x²-1)²-18(x²-1)+27
=3[(x²-1)²-6(x²-1)+9]
=3(x²-1-3)²
=3(x²-4)²
=3(x+2)²(x-2)²