用因式分解法解方程:(2x-1)(3x+4)=2x-1.

问题描述:

用因式分解法解方程:(2x-1)(3x+4)=2x-1.

(2x-1)(3x+4)=2x-1
(2x-1)(3x+4)-(2x-1)=0
(2x-1)[(3x+4)-1]=0
x1=1/2,x2=1

(2x-1)(3x+4)=2x-1.
(2x-1)(3x+4)-(2x-1)=0
(2x-1)(3x+4-1)=0
x=1/2或者x=-1

(2x-1)(3x+4)=2x-1.
(2x-1)(3x+4)-(2x-1)=0
(2x-1)(3x+4-1)=0
(2x-1)(3x+3)=0
x=1/2或x=-1