计算:(a-b)²-(3a²-3ab+b²)

问题描述:

计算:(a-b)²-(3a²-3ab+b²)

(a-b)^2-(3a^2-3ab+b^2)
=a^2-2ab+b^2-3a^2+3ab-b^2
=-2a^2+ab

a^2-2ab+b^2-3a^2+3ab-b^2
=-2a^2+ab
=a(b-2a)

(a-b)²-(3a²-3ab+b²)
=a²-2ab+b²-3a²+3ab-b²
=ab-2a²