cos2(π/4+α)+cos2(π/4-α)= (2是平方)

问题描述:

cos2(π/4+α)+cos2(π/4-α)= (2是平方)

[cos(π/4+α)]^2+[cos(π/2-(π/4+α))]^2
=[cos(π/4+α)]^2+[sin(π/4+α)]^2
=1