x+2y=0(x≠0),求分式x²-xy分之2xy+y²

问题描述:

x+2y=0(x≠0),求分式x²-xy分之2xy+y²

x=-2yx²-xy分之2xy+y²=【2(-2y)y+y²】/【(-2y)²-(-2y)y】=-3y²/6y²=-0.5