x^2-xy-2y^2-x+5y-2因式分解过程要详细、谢谢

分类: 作业答案 • 2021-12-19 15:40:59

问题描述：

答

（x+y-2)(x-2y+1) :
x^2-xy-2y^2-x+5y-2=
x^2+xy-2x--2xy-2y^2+4y+x+y-2=
(x+y-2)x-(x+y-2)(-2y)+(x+y-2)=
（x+y-2)(x-2y+1)

答

=(x+y)(x-2y)-x+5y-2
=(x+y-2)(x-2y+1)

答

(x-2y)(x+y)+(-x+5y)-2=(x-2y+1)(x+y-2)
使用十字相乘法得来：
x-2y 1
x+y -2
=-2x+4y+x+y=-x+5y

答

x^2-xy-2y^2-x+5y-2
＝(x-2y)(x+y)-2(x-2y)+(x+y)-2
=(x-2y+1)*(x+y-2)

x^2-xy-2y^2-x+5y-2因式分解 过程要详细、谢谢