已知x的平方—xy=-12,分别求式子x的平方—y的平方与x的平方—2xy+y的平方的值.

结果有无数个。正整数结果有以下几个：
x的平方—xy=-12 x(y-x)=12=1X12=2X6=3X4=4X3=6X2=12X1
x=1，y=13时：x^2-y^2=-168，x^2-2xy+y^2=(x-y)^2=144
x=2，y=8时：x^2-y^2=-60，x^2-2xy+y^2=(x-y)^2=36
x=3，y=7时：x^2-y^2=-40，x^2-2xy+y^2=(x-y)^2=16
x=4，y=7时：x^2-y^2=-33，x^2-2xy+y^2=(x-y)^2=9
x=6，y=8时：x^2-y^2=-28，x^2-2xy+y^2=(x-y)^2=4
x=12，y=13时：x^2-y^2=-25，x^2-2xy+y^2=(x-y)^2=1
希望采纳，谢谢

结果有无数个.正整数结果有以下几个：
x的平方—xy=-12 x(y-x)=12=1X12=2X6=3X4=4X3=6X2=12X1
x=1,y=13时：x^2-y^2=-168,x^2-2xy+y^2=(x-y)^2=144
x=2,y=8时：x^2-y^2=-60,x^2-2xy+y^2=(x-y)^2=36
x=3,y=7时：x^2-y^2=-40,x^2-2xy+y^2=(x-y)^2=16
x=4,y=7时：x^2-y^2=-33,x^2-2xy+y^2=(x-y)^2=9
x=6,y=8时：x^2-y^2=-28,x^2-2xy+y^2=(x-y)^2=4
x=12,y=13时：x^2-y^2=-25,x^2-2xy+y^2=(x-y)^2=1