已知x-y=4,xy=-2,则代数式(3x-4y+5xy)-(2x-3y-2xy)的值是多少

问题描述:

已知x-y=4,xy=-2,则代数式(3x-4y+5xy)-(2x-3y-2xy)的值是多少

(3x-4y+5xy)-(2x-3y-2xy)=3x-4y+5xy-2x+3y+2xy=x-y+7xy
x-y=4,xy=-2,
所以(3x-4y+5xy)-(2x-3y-2xy)=x-y+7xy=4-14=-10

=3x-4y+5xy-2x+3y+2xy=x-y+7xy=4+7*(-2)=4-14=-10

(3x-4y+5xy)-(2x-3y-2xy)
=3x-4y+5xy-2x+3y+2xy
=x-y+7xy
=4+7×(-2)
=4-14
=-10

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