求r=三次根下3V/4π的导数,因为我是预习的新课,所以麻烦写详细点,
问题描述：
求r=三次根下3V/4π的导数,因为我是预习的新课,所以麻烦写详细点,
答
r＝(1/3)*(3v/4π)^(1/3-1)*(3v/4π)'=(1/3)*(3v/4π)^(-2/3)*(3/4π)
整理一下，答案就是：(1/4π)*(3v/4π)^(-2/3)
答
r=(3V/4π)^(1/3)=(3/4π)^(1/3)*V^(1/3)
所以r'=(3/4π)^(1/3)*[V^(1/3)]'
=(3/4π)^(1/3)*[(1/3)*V^(1/3-1)]
=(3/4π)^(1/3)*(1/3)*V^(-2/3)
=(1/36π)*1/三次根下V^2