(2倍根号2-3)2011次方×(2倍根号2+3)2012次方,-3和+3不在根号2内!

问题描述:

(2倍根号2-3)2011次方×(2倍根号2+3)2012次方,-3和+3不在根号2内!

(2√2-3) ^2011×(2√2+3) ^2012
={(2√2-3) ×(2√2+3)} ^2011×(2√2+3)
=-1*×(2√2+3)
=-2√2-3

原式=[(2根号2-3)*(2根号2+3)]^2011*(2根号2+3)
=(-1)^2011*(2根号2+3)
=-2根号2-3