已知log3(2)=a,2^b=3,求lga+lgb的值

问题描述:

已知log3(2)=a,2^b=3,求lga+lgb的值

log3(2)=a,所以1/log2(3)=a,因为log2(3)=b.所以1/a=b.ab=1lga+lgb=lgab=lg1=0