已知log3(2)=a,2^b=3,求lga+lgb的值
问题描述:
已知log3(2)=a,2^b=3,求lga+lgb的值
答
log3(2)=a,所以1/log2(3)=a,因为log2(3)=b.所以1/a=b.ab=1lga+lgb=lgab=lg1=0
已知log3(2)=a,2^b=3,求lga+lgb的值
log3(2)=a,所以1/log2(3)=a,因为log2(3)=b.所以1/a=b.ab=1lga+lgb=lgab=lg1=0