若使式子1/(x-3)=(x+2)/(x^2-x-6)从左到右变形成立,

问题描述:

若使式子1/(x-3)=(x+2)/(x^2-x-6)从左到右变形成立,
应满足的条件是 A.x +2>0 B.x +2=0 C.x +2

1/(x-3)=(x+2)/(x²-x-6)
1/(x-3)=(x+2)/(x+2)(x-3)
左边要分子分母同时乘以 x+2可得到右边,那么必须满足 x+2≠0,选择D