若集合p={x|2x-a0},a,b属于N,且P交Q交N={1},则满足条件的整数对(a,b)的个数为

问题描述:

若集合p={x|2x-a0},a,b属于N,且P交Q交N={1},则满足条件的整数对(a,b)的个数为

P={x|2x-a0}
= { x | x > b/3}
P∩Q∩N = { x| b/3 => b = 1 or 2
a = 3 or 4
(a,b) = (3,1) or (3,2) or
(4,1) or (4,2)