已知x2+4x-2=0则代数式x4+3x3-5x2+6x+15=
问题描述:
已知x2+4x-2=0则代数式x4+3x3-5x2+6x+15=
答
x4+3x3-5x2+6x+15
=x²(x²+4x-2)-x³-3x²+6x+15
=-x³-3x²+6x+15
=-x(x²+4x-2)+x²+4x+15
=x²+4x+15
=x²+4x-2+17
=17