以CnHmCOOH所表示的羧酸0.1mol加成时需32g溴,0.1mol该羧酸完全燃烧,产生CO2和H2O共3.4mol,该羧酸是( ) A.C15H27COOH B.C15H31COOH C.C17H31COOH D.C17H33COO
问题描述:
以CnHmCOOH所表示的羧酸0.1mol加成时需32g溴,0.1mol该羧酸完全燃烧,产生CO2和H2O共3.4mol,该羧酸是( )
A. C15H27COOH
B. C15H31COOH
C. C17H31COOH
D. C17H33COOH
答
0.1mol加成时需32g溴,即n(Br2)=32g160g/mol=0.2mol,说明分子中含有2个C=C键,A、C15H27COOH中含有2个C=C键,0.1mol该羧酸完全燃烧,产生CO2和H2O共(1.6+1.4)mol=3.0mol,故A错误;B、C15H31COOH为饱和酸,不含...