若|3/2x-6|+(0.2+2y)2=0,则x2+y2=_.

问题描述:

若|

3
2
x-6|+(0.2+2y)2=0,则x2+y2=______.

由题意得,

3
2
x-6=0,0.2+2y=0,
解得x=4,y=-0.1,
所以x2+y2=42+(-0.1)2=16+0.01=16.01.
故答案为:16.01.