计算分式：[(4a^2-4a)/(a^2-2a+1)]/[(a+1)/(a-1)-(a-1)/(a+1)]*[1/(3a-3)]谢谢了,

分类: 作业答案 • 2023-01-20 15:02:15

问题描述：

答

[(4a^2-4a)/(a^2-2a+1)]/[(a+1)/(a-1)-(a-1)/(a+1)]*[1/(3a-3)] =[4a(a-1)/(a-1)^2]/[4a/(a+1)(a-1)]*[1/3(a-1)] =[4a/(a-1)]/[4a/3(a+1)(a-1)^2] =3(a+1)(a-1)