计算:(1)log2748+log212-12log242-1(2)0.027 −13-(-16)-2+2560.75+(13−1)0-3-1.

问题描述:

计算:
(1)log2

7
48
+log212-
1
2
log242-1
(2)0.027 
1
3
-(-
1
6
-2+2560.75+(
1
3
−1
0-3-1

(1)log2

7
48
+log212-
1
2
log242-1
=log2(
7
48
×12×
1
42
×
1
2
)

=log22
3
2
=-
3
2

(2)0.027 
1
3
-(-
1
6
-2+2560.75+(
1
3
−1
0-3-1
=0.3-1-36+64+1-
1
3

=32.
答案解析:(1)利用对数的运算法则和运算性质求解.
(2)利用根式与分数指数幂的运算法则求解.
考试点:根式与分数指数幂的互化及其化简运算;有理数指数幂的化简求值.
知识点:本题考查根式、分数指数幂、对数的化简求值,是基础题,解题时要注意运算法则的合理运用.