丨x-1丨+(y+3)²=0求1-xy=xy²的值

问题描述:

丨x-1丨+(y+3)²=0求1-xy=xy²的值
丨x-1丨+(y+3)²=0求1-xy=xy²的值

丨x-1丨+(y+3)²=0
x-1=0,y+3=0
x=1,y=-3
1-xy+xy²=1-1*(-3)+1*9=1+3+9=13