解不等式: (1)x2+2x-3≤0; (2)x-x2+6<0.
问题描述:
解不等式:
(1)x2+2x-3≤0; (2)x-x2+6<0.
答
(1)∵x2+2x-3≤0,
∴(x+3)(x-1)≤0,
∴-3≤x≤1;
(2)∵x-x2+6<0,
∴x2-x-6>0,
∴(x+2)(x-3)>0,
∴x<-2或x>3.