先化简,再求值:(x+2y)2-2(x-y)(x+y)+2y(x-3y),其中x=-2,y=1/2.

问题描述:

先化简,再求值:(x+2y)2-2(x-y)(x+y)+2y(x-3y),其中x=-2,y=

1
2

原式=x2+4xy+4y2-2(x2-y2)+2xy-6y2
=x2+4xy+4y2-2x2+2y2+2xy-6y2
=-x2+6xy,
当x=-2,y=

1
2
时,
原式=-(-2)2+6×(-2)×
1
2
=-4-6=-10.