(根号2/1+i)的2010次方等于
问题描述:
(根号2/1+i)的2010次方等于
答
[√2/(1+i)]^2
=2/(1+2i-1)
=1/i
=i/i^2
=-i
所以原式=(-i)^1005
=-i^1005
=-i^(4*251+1)
=-i