已知x2-5x-2006=0,求(x−2)3−(x−1)2+1x−2的值.

问题描述:

已知x2-5x-2006=0,求

(x−2)3−(x−1)2+1
x−2
的值.

(x−2)3−(x−1)2+1
x−2
=
(x−2)3−x(x−2)
x−2

=(x-2)2-x,
=x2-5x+4,
∵x2-5x-2006=0,
∴x2-5x=2006,
∴x2-5x+4=2006+4=2010.
故答案为:2010.