x-1/6[36-12(3/5x+1)]=1/3x-2
问题描述:
x-1/6[36-12(3/5x+1)]=1/3x-2
答
解∶x-1/6[36-12(3/5x+1)]=(1/3)x-2x-1/6[36-(36/5)x-12]=(1/3)x-2 x-6+6/5x+2=(1/3)x-2 x+6/5x-(1/3)x=-2+6-2 (28/15)x=2 x=15/14