cosπ/3+tanπ/4+3tan²π/6+sinπ/2+cosπ+sin3π/2等于?.
问题描述：
cosπ/3+tanπ/4+3tan²π/6+sinπ/2+cosπ+sin3π/2等于?.
答
cosπ/3+tanπ/4+3tan²π/6+sinπ/2+cosπ+sin3π/2
=1/2 + 1 + 3*(根号3/3)² + 1 - 1 - 1
=1/2 + 3*(1/3)
=1/2+1
=3/2