[2x/(2x-1)]-2=[x/(2-x)] 2+[18/(x^2-16)]=(2x-1)/(x+4)
问题描述：
[2x/(2x-1)]-2=[x/(2-x)] 2+[18/(x^2-16)]=(2x-1)/(x+4)
解方程
答
[2x/(2x-1)]-2=[x/(2-x)]
(2x-4x+2)/(2x-1)=x/(2-x)
(2-2x)/(2x-1)=x/(2-x)
2x²-x=4+2x²-6x
5x=4
x=4/5
2+[18/(x^2-16)]=(2x-1)/(x+4)
2x²-32+18=2x²-9x+4
9x=18
x=2