tan(-150°)cos(-210°)cos(-420°)tan(-600°)/sin(-1050°)
问题描述:
tan(-150°)cos(-210°)cos(-420°)tan(-600°)/sin(-1050°)
答
tan(-150°)cos(-210°)cos(-420°)tan(-600°)/sin(-1050°)
=tan30°(-cos30°)cos60°tan60°/sin30°
=-sin30°sin60°/sin30°
=-√3/2