(1+3+5+··+2001+2003)-(2+4+6+··+2000+2002)
问题描述:
(1+3+5+··+2001+2003)-(2+4+6+··+2000+2002)
简便计算
答
(1 + 3 + 5+ ...+ 2001 + 2003)-(2 + 4 + 6 +··+ 2000 + 2002)
= 1 + (3 - 2) + (5 - 4) + ...+ (2001 - 2000) + (2003 - 2002)
= 1 + 1×1001
= 1002