(4a+2b-1)(4a-2b+1）(4a+2b-1)^2-(4a-2b+1)^2
问题描述：
(4a+2b-1)(4a-2b+1）(4a+2b-1)^2-(4a-2b+1)^2
两个算式,各等于多少?
答
(4a+2b-1)(4a-2b+1)=[4a+(2b-1)][4a-(2b-1)]=(4a)^2-(2b-1)^2=16a^2-4b^2+4b-1(4a+2b-1)^2-(4a-2b+1)^2=[(4a+2b-1)+(4a-2b+1)][(4a+2b-1)-(4a-2b+1)]=(8a)(4b-2)=32ab-16a