the double ninth festival

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• a long time ago,two friends lived in a palace and worked for the king.one of these boys _1_ a girl very much and he wanted to give her a present.one afternoon,he and his friend _2_a big vase with some beautiful flowers in it.he _3_up and took one for the girl.the next day he did the _4_thing,and the third day,and the fourth day...until the morning of the ninth day.the king noticed very _5_flowers were left in the vase.he was so angry that he called _6
• 10^(-7);++n){P += ((-1)^(n+1))*(1/(2*n-1));}pi = P*4;cout" target="_blank"> 使用C++,求pi的近似值用下面的公式求pi的近似值pi/4 = 1-1/3+1/5-1/7+.直到最后一项的绝对值小于10的-7次方为止如下式我自己编的#include "stdafx.h"#include "iostream"#include "cmath"#include "conio.h"using namespace std;int _tmain(int argc,_TCHAR* argv[]){int n = 1;double P = 0,pi;for(n=1;1/(2*n-1) > 10^(-7);++n){P += ((-1)^(n+1))*(1/(2*n-1));}pi = P*4;cout
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• Dear sweetie,Happy Double Ninth Festival.double ninth festival 翻译是什么?