4a²b²-(a²+b²)²
问题描述:
4a²b²-(a²+b²)²
答
要分解因式吗?如果是,则解:4a²b²-(a²+b²)²=[2ab+(a²+b²)][2ab-(a²+b²)]=(a+b)²[-(a²+b²-2ab)]=(a+b)²[-(a-b)²]=-(a+b)²(a-b)²...
4a²b²-(a²+b²)²
要分解因式吗?如果是,则解:4a²b²-(a²+b²)²=[2ab+(a²+b²)][2ab-(a²+b²)]=(a+b)²[-(a²+b²-2ab)]=(a+b)²[-(a-b)²]=-(a+b)²(a-b)²...