分解因式：X的8次方—X的6次方—X平方+1
问题描述：
分解因式：X的8次方—X的6次方—X平方+1
答
= x^6(x^2-1)-(x^2-1)
=(x^6-1)(x^2-1)
=(x^2-1)(x^4+x^2+1)(x^2-1)
=(x^2-1)^2(x^4+2x^2+1-x^2)
=(x^2-1)^2[(x^2+1)^2-x^2]
=(x+1)^2(x-1)^2(x^2+x+1)(x^2-x+1)