已知弧长1138mm,弦长750mm求半径、拱高?
问题描述：
已知弧长1138mm,弦长750mm求半径、拱高?
答
已知弧长C=1138mm,弦长L=750mm求半径R、拱高H?
弧所对的圆心角为A.
Rn+1=(1+(L-2*Rn*SIN(C/(2*Rn)))/(L-C*COS(C/(2*Rn))))*Rn
R0=350
R1=371.99
R2=375.51
R3=375.59
R4=375.59
R=375.59mm
A=C/R
=1138/375.59
=3.0299弧度
=3.0299*180/PI
=173.6度
H=R-R*COS(A/2)
=375.59-375.59*COS(173.6/2)
=354.626mm