1949×(1/51−1/2000)+51×(1/1949−1/2000)−2000×(1/1949+1/51)+3.
问题描述:
1949×(
−1 51
)+51×(1 2000
−1 1949
)−2000×(1 2000
+1 1949
)+3. 1 51
答
1949×(
-1 51
)+51×(1 2000
-1 1949
)-2000×(1 2000
+1 1949
)+3,1 51
=
-949 51
+1949 2000
-51 1949
-51 2000
-2000 1949
,2000 51
=(
-1949 51
)+(2000 51
-51 1949
)-(2000 1949
+1919 2000
)+3,51 1949
=-1-1-1+3,
=0.