4a^2b-[3ab^2-(3a^2b-1)],其中a=-0.1,b=1.

分类: 作业答案 • 2023-01-08 18:04:10

问题描述：

答

4a^2b-[3ab^2-(3a^2b-1)]
=4a^2b-3ab^2+(3a^2b-1)
=4a^2b-3ab^2+3a^2b-1
=7a^2b-3ab^2-1
=7×0.01×1-3×(-0.1)×1-1
=0.07+0.3-1
=-0.63