根号下x^2-1÷xy-y (x>1,y>0) 化成最简二次根式

问题描述:

根号下x^2-1÷xy-y (x>1,y>0) 化成最简二次根式

x>1 y>0
√[(x²-1)/(xy-y)]
=√[(x+1)(x-1)/y(x-1)]
=√[(x+1)/y]
=√(xy+y)/y