用代入消元法解方程组 3(y-2)=x-17,2(x-1)=5y-8
问题描述:
用代入消元法解方程组 3(y-2)=x-17,2(x-1)=5y-8
答
3(y-2)=x-17,
3y-6=x-17
所以x=3y+11
代入2(x-1)=5y-8
2(3y+11-1)=5y-8
6y+20=5y-8
y=-28
x=3y+11=-73