(NH4)2SO4==>SO2+N2+NH3+H2O
问题描述：
(NH4)2SO4==>SO2+N2+NH3+H2O
这个方程用得失电子守恒怎么配平啊,
答
(NH4)2SO4==>SO2+N2+NH3+H2O升2降3*2*3*1(NH4)2SO4==>(3)SO2+(1)N2+NH3+H2O(3)(NH4)2SO4==>3SO2+N2+NH3+H2O3(NH4)2SO4==>3SO2+N2+(4)NH3+(6)H2O